Alkoxymercuration of alkynes involves formation of an organomercury intermediate (I) which is reduced with sodium borohydride to give the final ether product.


Screenshot 2024 01 16 191633

Screenshot 2024 01 16 191633

Step 1 of 2

Given is the alkoxymercuration of alkenes involves formation of an organomercury intermediate (I) which is reduced with sodium borohydride ton give the final ether product.

We have to found out the intermediate (I) for the reaction given below.

Hg(O₂CCH₃)₂INaBH₄Product(CH3)2CHOH

Explanation:

Here we use the concept of oxymercuration and demercuartion of alkene with sterereochemistry.

Step 2 of 2

As seen in the reaction following happens after applying oxymercuration concepts.

Hg(O₂CCH₃)₂(CH3)2CHOHOHgHCH3CH3CH3CH3I=IntermediThis is oxymercuration in presence of isopropyl alcohol intermediate product.

Final solution

This is type of oxymercuration in presence of isopropyl alcohol and after that is demercuration in presence of NaBH4 which form alcohol.

 

 

 

Leave a Reply

Your email address will not be published. Required fields are marked *

Call Now Button