Balance the reaction between Cl- and BR2 to form ClO- and Br- in basic Solution.


Screenshot 2024 01 28 132923

Screenshot 2024 01 28 132923

Step 1 of 3

Given data: given the ions Cl− and Br2 to form ClO− and Br−

 

Find: Enter the coefficients in the blank.

Explanation:

First, count the atoms on each side. Second, change the coefficient of one of the substances. Third, count the numbers of atoms again and, from there, repeat steps two and three until you’ve balanced the equation.

 

Step 2 of 3

Part A.

To balance the reaction between Cl− and Br2 to form ClO− and Br− in basic solution, we can follow these steps:

  1. Write the unbalanced equation:

Cl−+Br2⟶ClO−+Br−

  1. Balance the non-oxygen and non-hydrogen elements first:

Cl−+Br2⟶ClO−+Br2

  1. Balance the oxygen atoms by adding water molecules:

Cl−+Br2⟶ClO−+Br−+H2O

  1. Balance the hydrogen atoms by adding hydrogen ions (H+):

Cl−+Br2+H2O⟶ClO−+Br−+H++H2O

  1. Balance the charges by adding electrons (e-):

Cl−+Br2+H2O⟶ClO−+Br−+H++H2O+2e−

The balanced equation is:

2Cl−+Br2+2H2O⟶2ClO−+2Br−+2H++H2O+2e−

 

In the balanced equation, water appears as a product with a coefficient of 1.

 

The number of electrons transferred in this reaction is 2.

Explanation:

Hence, the balanced equation is:

2Cl−+Br2+2H2O⟶2ClO−+2Br−+2H++H2O+2e−

 

Step 3 of 3

Part B.

To balance the reaction between N2​H4​ and Br2​ to form NH3​ and BrO3−​ in basic solution, we can follow these steps:

N2​H4​+Br2​⟶NH3​+BrO3−​

  1. Balance the non-oxygen and non-hydrogen atoms first:

N2​H4​+Br2​⟶NH3​+BrO3−​

 

  1. Balance oxygen atoms by adding water molecules (HO):

N2​H4​+Br2​⟶NH3​+BrO3−​+H2​O

 

  1. Balance hydrogen atoms by adding H ions:

N2​H4​+Br2​+2OH−⟶NH3​+BrO3−​+H2​O

 

  1. Balance the charge by adding electrons (e):
    N2​H4​+Br2​+2OH−⟶NH3​+BrO3−​+H2​O + 2e−

Now, check the balancing:

  • Nitrogen: 2 on both sides
  • Hydrogen: 4 on both sides
  • Bromine: 2 on both sides
  • Oxygen: 4 on both sides
  • Charge: 0 on both sides

The balanced equation is:

N2H4​+Br2​+2OH−⟶NH3​+BrO3−​+H2O + 2e−

Hence, N2H4+4Br2⟶2NH3+4BrO3−

Water appears in the balanced equation as a reactant with a coefficient of 2.

In this reaction, 12 electrons are transferred.

Explanation:

The balanced chemical equation for the reaction between N2H4 and Br2 to form NH3 and BrO3- in basic solution is:

N2H4+4Br2⟶2NH3+4BrO3−

Final solution

Part A.

The balanced equation is:

2Cl−+Br2+2H2O⟶2ClO−+2Br−+2H++H2O+2e−

In the balanced equation, water appears as a product with a coefficient of 1.

The number of electrons transferred in this reaction is 2.

Part B.

therefore, balanced equation is

N2H4+4Br2⟶2NH3+4BrO3−

Water appears in the balanced equation as a reactant with a coefficient of 2.

In this reaction, 12 electrons are transferred.

 

Leave a Reply

Your email address will not be published. Required fields are marked *

Call Now Button