The concentrations of Fe2+ and o-phen used in an experiment were 0.00136 M and 0.00407 M, respectively. If a student found a stoichimetric volume ratio of 2.0 mL o-phen to 1.0 mL Fe2+, what is the stoichiometric mole ratio of o-phen to Fe2+? Give your answer to two significant figures.


Step 1 of 2

Given data: Concentration of Fe2+=0.00136M

Concentration of �-phen=0.00407M

Volume ratio of �-phen to Fe2+=2.0mL �-phen: 1.0mL Fe2+

find: we have to determine the stoichiometric mole ratio of �-phen to Fe2+.

Explanation:

we need to compare the number of moles of �-phen to the number of moles of Fe2+.

Step 2 of 2

First, we need to calculate the moles of Fe2+ and �-phen using the given concentrations and volumes:

Moles of Fe2+ = Concentration of Fe2+ × Volume of Fe2+

Moles of �-phen = Concentration of �-phen × Volume of �-phen

For the volume ratio, we can assume that the volumes are directly proportional to the number of moles.

Therefore, the stoichiometric mole ratio is equal to the volume ratio.

Moles of �-phen / Moles of Fe2+ = Volume of �-phen/ Volume of Fe2+

= 2.0m/L1.0mL

Now, let’s substitute the given values:

Moles of �-phen / Moles of Fe2+ = 2.0mL/1.0mL = 2.0

Explanation:

Therefore, the stoichiometric mole ratio of �-phen to Fe2+ is 2.0

Final solution

Hence we can write the stoichiometric mole ratio of �-phen to Fe2+ is 2.0 in two significant figures.

 

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