### Step 1 of 2

Given data: a current of 680 mA flows through a copper wire for 30 minutes.

Find: we need to calculate how many moles of electrons travel through the wire.

**Explanation:**

To calculate the moles of electrons (*n*) that flow through a wire, you can use Faraday’s constant (*F*) and the formula:

n=I⋅tF

### Step 2 of 2

The wire is traversed by

1.27×10−2 moles of electrons. A copper wire experiences a 0.680mA current flow for several minutes. The electron is a subatomic particle with a negative electric charge.

Due to their lack of known components or substructure, electrons, which are part of the first generation of the lepton particle family, are typically considered to be elementary particles.

The mole is a unit of measurement or the starting point for determining how much of a substance is present in a sample.

A mole is the Avogadro number of molecules.

q=i×t

The terms “charge,” “current,” and “time” are used here:

I=680mA×1A/1,000mA

I=0.680A

60sec/1min=30minutes

t=1,800sec

q=I+tq=0.680+1,800×q

q=1,224 Amp.sec

q=1,224C(col=amp×sec)

Charge=moles of electrons× charge of an electron

Charge of an electron=96500C/mol of e−

1224C=moles of electrons× 96500C/mol of e−

Moles of electrons=1224C / (96500C/mol of �-)

**Explanation:**

Moles of electrons=1.27×10−2 moles of e−

##### Final solution

Therefore, 1.27×10−2 moles of electrons travel through the wire.