Draw the furanose form of the product created when D-xylose is treated with C6H5NH2, mind H+.


Screenshot 2024 01 27 181431

Screenshot 2024 01 27 181431

Step 1 of 2

Given data: Given is the D-xylose which is when treated with C6H5CH2NH2.

 

Find: Draw the furanose.

Explanation:

To draw the furanose form of the product created when D-xylose is treated with C6H5CH2NH2(benzylamine) under mild acidic conditions, we need to consider the reaction between the two compounds.

 

Step 2 of 2

D-xylose is a 5-carbon sugar, and benzylamine is an amine compound. The reaction between D-xylose and benzylamine under mild acidic conditions would likely involve the formation of a glycosidic bond, resulting in a glycoside compound.

 

The furanose form of the glycoside compound can be represented as follows:

 

In this representation:

  • The five-membered ring is indicated.
  • HO represents a hydroxyl group.
  • CH2OH represents the CH2OH group in the original D-xylose.
  • CH2Ph represents the benzyl group (C6H5CH2) attached to the sugar molecule.

Explanation:

In this structure, the oxygen atom represents the glycosidic bond between D-xylose and benzylamine. The CH2OH group represents the remaining portion of D-xylose, and the C6H5 group represents the benzylamine.

 

Final solution

Hence the final reaction is:

D- xyloseFuranose

Screenshot 2024 01 27 181541

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