4.00 mL of H2O, 3.25 mL of an aqueous 0.030 M SCN- solution, and 11.00 mL of an aqueous 0.020 M Fe3+ solution were mixed together. The total volume of the new solution was 18.25 mL. What is the diluted Fe3+ concentration in the new solution?


Step 1 of 2

Given data:

Initial volume of Fe3+ solution (V1) = 11.00mL

Initial concentration of Fe3+ solution (M1) = 0.020M

Final volume of the new solution (V2) = 18.25mL

Find: find the diluted Fe3+ concentration in the new solution.

Explanation:

To determine the diluted Fe3+ concentration in the new solution, we can use the principle of conservation of moles. The moles of Fe3+ in the final solution should be equal to the sum of the moles of Fe3+ in the initial Fe3+ solution.

Step 2 of 2

The moles of Fe³⁺ can be calculated using the formula:

moles = molarity × volume

Therefore,

M1V1=M2V2

where:

M1 = initial concentration of Fe3+ solution

V1 = initial volume of Fe3+ solution

M2 = final concentration of Fe3+ solution

V2 = final volume of Fe3+ solution

We can rearrange the equation to solve for M2:

M2=M1V1V2

Substituting the given values:

M2=0.020M×11.00mL18.25mL

M2=0.01212M

Explanation:

Therefore, the diluted Fe3+ concentration in the new solution is approximately 0.01212M.

Final solution

Hence, using the formula M2=M1V1V2 we have calculated the diluted Fe3+ concentration in the new solution is approximately 0.01212M.

 

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